(2z+5)=(4z-5)

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Solution for (2z+5)=(4z-5) equation: 



(2z+5)=(4z-5)

We move all terms to the left:

(2z+5)-((4z-5))=0

We get rid of parentheses

2z-((4z-5))+5=0



We calculate terms in parentheses: -((4z-5)), so:

(4z-5)

We get rid of parentheses

4z-5

Back to the equation:

-(4z-5)



We get rid of parentheses

2z-4z+5+5=0

We add all the numbers together, and all the variables

-2z+10=0

We move all terms containing z to the left, all other terms to the right

-2z=-10

z=-10/-2

z=+5

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