2(3x-4)=4x+32

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Solution for 2(3x-4)=4x+32 equation: 



2(3x-4)=4x+32

We move all terms to the left:

2(3x-4)-(4x+32)=0

We multiply parentheses

6x-(4x+32)-8=0

We get rid of parentheses

6x-4x-32-8=0

We add all the numbers together, and all the variables

2x-40=0

We move all terms containing x to the left, all other terms to the right

2x=40

x=40/2

x=20

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