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4(x+5)=2(x-40)
We move all terms to the left:
4(x+5)-(2(x-40))=0
We multiply parentheses
4x-(2(x-40))+20=0
We calculate terms in parentheses: -(2(x-40)), so:We get rid of parentheses
2(x-40)
We multiply parentheses
2x-80
Back to the equation:
-(2x-80)
4x-2x+80+20=0
We add all the numbers together, and all the variables
2x+100=0
We move all terms containing x to the left, all other terms to the right
2x=-100
x=-100/2
x=-50
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