4(x+5)+7x=29+11(x-3)

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Solution for 4(x+5)+7x=29+11(x-3) equation: 



4(x+5)+7x=29+11(x-3)

We move all terms to the left:

4(x+5)+7x-(29+11(x-3))=0

We add all the numbers together, and all the variables

7x+4(x+5)-(29+11(x-3))=0

We multiply parentheses

7x+4x-(29+11(x-3))+20=0



We calculate terms in parentheses: -(29+11(x-3)), so:

29+11(x-3)

determiningTheFunctionDomain
11(x-3)+29

We multiply parentheses

11x-33+29

We add all the numbers together, and all the variables

11x-4

Back to the equation:

-(11x-4)



We add all the numbers together, and all the variables

11x-(11x-4)+20=0

We get rid of parentheses

11x-11x+4+20=0

We add all the numbers together, and all the variables

24!=0

There is no solution for this equation

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