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4x(2x-3)-3x=4x+2x
We move all terms to the left:
4x(2x-3)-3x-(4x+2x)=0
We add all the numbers together, and all the variables
4x(2x-3)-3x-(+6x)=0
We add all the numbers together, and all the variables
-3x+4x(2x-3)-(+6x)=0
We multiply parentheses
8x^2-3x-12x-(+6x)=0
We get rid of parentheses
8x^2-3x-12x-6x=0
We add all the numbers together, and all the variables
8x^2-21x=0
a = 8; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·8·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*8}=\frac{0}{16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*8}=\frac{42}{16} =2+5/8 $
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