4(x+4)=10(x-2)

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Solution for 4(x+4)=10(x-2) equation: 



4(x+4)=10(x-2)

We move all terms to the left:

4(x+4)-(10(x-2))=0

We multiply parentheses

4x-(10(x-2))+16=0



We calculate terms in parentheses: -(10(x-2)), so:

10(x-2)

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

4x-10x+20+16=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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