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x-(3-2x)=10+4x^2)
We move all terms to the left:
x-(3-2x)-(10+4x^2))=0
We add all the numbers together, and all the variables
-(10+4x^2))+x-(-2x+3)=0
We add all the numbers together, and all the variables
-(10+4x^2))+x-(-2x=0
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