4(x+3)=x+27

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Solution for 4(x+3)=x+27 equation: 



4(x+3)=x+27

We move all terms to the left:

4(x+3)-(x+27)=0

We multiply parentheses

4x-(x+27)+12=0

We get rid of parentheses

4x-x-27+12=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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