2+3(3k-5)=-5(4-2k)

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Solution for 2+3(3k-5)=-5(4-2k) equation: 



2+3(3k-5)=-5(4-2k)

We move all terms to the left:

2+3(3k-5)-(-5(4-2k))=0

We add all the numbers together, and all the variables

3(3k-5)-(-5(-2k+4))+2=0

We multiply parentheses

9k-(-5(-2k+4))-15+2=0



We calculate terms in parentheses: -(-5(-2k+4)), so:

-5(-2k+4)

We multiply parentheses

10k-20

Back to the equation:

-(10k-20)



We add all the numbers together, and all the variables

9k-(10k-20)-13=0

We get rid of parentheses

9k-10k+20-13=0

We add all the numbers together, and all the variables

-1k+7=0

We move all terms containing k to the left, all other terms to the right

-k=-7

k=-7/-1

k=+7

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