4(x+3)=3(2x+1)+1

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Solution for 4(x+3)=3(2x+1)+1 equation: 



4(x+3)=3(2x+1)+1

We move all terms to the left:

4(x+3)-(3(2x+1)+1)=0

We multiply parentheses

4x-(3(2x+1)+1)+12=0



We calculate terms in parentheses: -(3(2x+1)+1), so:

3(2x+1)+1

We multiply parentheses

6x+3+1

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

4x-6x-4+12=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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