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(2x+1)(x+4)=22.
We move all terms to the left:
(2x+1)(x+4)-(22.)=0
We add all the numbers together, and all the variables
(2x+1)(x+4)-22=0
We multiply parentheses ..
(+2x^2+8x+x+4)-22=0
We get rid of parentheses
2x^2+8x+x+4-22=0
We add all the numbers together, and all the variables
2x^2+9x-18=0
a = 2; b = 9; c = -18;
Δ = b2-4ac
Δ = 92-4·2·(-18)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-15}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+15}{2*2}=\frac{6}{4} =1+1/2 $
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