4(x+3)-4=8(1/2x=1)

Solution for 4(x+3)-4=8(1/2x=1) equation:

4(x+3)-4=8(1/2x=1)

We move all terms to the left:

4(x+3)-4-(8(1/2x)=0


Domain of the equation: 2x)-4!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4(x+3)-(8(+1/2x)-4=0

We multiply parentheses

4x-(8(+1/2x)-4+12=0

We multiply all the terms by the denominator


4x*2x)-4+12-(8(+1=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$