12(x-2)+3x=1/3(x+12)+10-x

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Solution for 12(x-2)+3x=1/3(x+12)+10-x equation: 



12(x-2)+3x=1/3(x+12)+10-x

We move all terms to the left:

12(x-2)+3x-(1/3(x+12)+10-x)=0



Domain of the equation: 3(x+12)+10-x)!=0

We move all terms containing x to the left, all other terms to the right

3(x+12)-x)!=-10

x∈R



We add all the numbers together, and all the variables

3x+12(x-2)-(1/3(x+12)+10-x)=0

We multiply parentheses

3x+12x-(1/3(x+12)+10-x)-24=0

We multiply all the terms by the denominator


3x*3(x+12)-x)+12x*3(x+12)+10-x)-(1-24*3(x+12)+10-x)+10=0

Wy multiply elements

9x^2(x-x)+12x*3(x+12)-x)-(1-24*3(x+12)-x)+10+10+10=0

We add all the numbers together, and all the variables

9x^20+12x*3(x+12)-x)-(1-24*3(x+12)-x)+10+10+10=0

Wy multiply elements

9x^20+36x^2(x-x)-(1-72x(x-x)+10+10+10=0

We do not support expression: x^20

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