4(x+3)+5(x+2)=20

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Solution for 4(x+3)+5(x+2)=20 equation: 



4(x+3)+5(x+2)=20

We move all terms to the left:

4(x+3)+5(x+2)-(20)=0

We multiply parentheses

4x+5x+12+10-20=0

We add all the numbers together, and all the variables

9x+2=0

We move all terms containing x to the left, all other terms to the right

9x=-2

x=-2/9

x=-2/9

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