-(2y-3)+19=8(2y+3)+7

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Solution for -(2y-3)+19=8(2y+3)+7 equation: 



-(2y-3)+19=8(2y+3)+7

We move all terms to the left:

-(2y-3)+19-(8(2y+3)+7)=0

We get rid of parentheses

-2y-(8(2y+3)+7)+3+19=0



We calculate terms in parentheses: -(8(2y+3)+7), so:

8(2y+3)+7

We multiply parentheses

16y+24+7

We add all the numbers together, and all the variables

16y+31

Back to the equation:

-(16y+31)



We add all the numbers together, and all the variables

-2y-(16y+31)+22=0

We get rid of parentheses

-2y-16y-31+22=0

We add all the numbers together, and all the variables

-18y-9=0

We move all terms containing y to the left, all other terms to the right

-18y=9

y=9/-18

y=-1/2

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