4(x+3)+12=15-5(x+6)

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Solution for 4(x+3)+12=15-5(x+6) equation:



4(x+3)+12=15-5(x+6)
We move all terms to the left:
4(x+3)+12-(15-5(x+6))=0
We multiply parentheses
4x-(15-5(x+6))+12+12=0
We calculate terms in parentheses: -(15-5(x+6)), so:
15-5(x+6)
determiningTheFunctionDomain -5(x+6)+15
We multiply parentheses
-5x-30+15
We add all the numbers together, and all the variables
-5x-15
Back to the equation:
-(-5x-15)
We add all the numbers together, and all the variables
4x-(-5x-15)+24=0
We get rid of parentheses
4x+5x+15+24=0
We add all the numbers together, and all the variables
9x+39=0
We move all terms containing x to the left, all other terms to the right
9x=-39
x=-39/9
x=-4+1/3

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