X(4x-9)=(4x+6)(x-3)

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Solution for X(4x-9)=(4x+6)(x-3) equation: 



X(4X-9)=(4X+6)(X-3)

We move all terms to the left:

X(4X-9)-((4X+6)(X-3))=0

We multiply parentheses

4X^2-9X-((4X+6)(X-3))=0

We multiply parentheses ..

4X^2-((+4X^2-12X+6X-18))-9X=0



We calculate terms in parentheses: -((+4X^2-12X+6X-18)), so:

(+4X^2-12X+6X-18)

We get rid of parentheses

4X^2-12X+6X-18

We add all the numbers together, and all the variables

4X^2-6X-18

Back to the equation:

-(4X^2-6X-18)



We add all the numbers together, and all the variables

4X^2-9X-(4X^2-6X-18)=0

We get rid of parentheses

4X^2-4X^2-9X+6X+18=0

We add all the numbers together, and all the variables

-3X+18=0

We move all terms containing X to the left, all other terms to the right

-3X=-18

X=-18/-3

X=+6

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