4(x+2)=2(3x+2)+2(x-4)

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Solution for 4(x+2)=2(3x+2)+2(x-4) equation: 



4(x+2)=2(3x+2)+2(x-4)

We move all terms to the left:

4(x+2)-(2(3x+2)+2(x-4))=0

We multiply parentheses

4x-(2(3x+2)+2(x-4))+8=0



We calculate terms in parentheses: -(2(3x+2)+2(x-4)), so:

2(3x+2)+2(x-4)

We multiply parentheses

6x+2x+4-8

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

4x-8x+4+8=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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