1/2x-20-x=3(2x-1)-(2x-1)-(2x-1)

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Solution for 1/2x-20-x=3(2x-1)-(2x-1)-(2x-1) equation: 



1/2x-20-x=3(2x-1)-(2x-1)-(2x-1)

We move all terms to the left:

1/2x-20-x-(3(2x-1)-(2x-1)-(2x-1))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We add all the numbers together, and all the variables

-1x+1/2x-(3(2x-1)-(2x-1)-(2x-1))-20=0

We multiply all the terms by the denominator


-1x*2x-((3(2x-1)-(2x-1)-(2x-1)))*2x-20*2x+1=0

Wy multiply elements

-2x^2-((3(2x-1)-(2x-1)-(2x-1)))*2x-40x+1=0

We add all the numbers together, and all the variables

-2x^2-40x-((3(2x-1)-(2x-1)-(2x-1)))*2x+1=0

We move all terms containing x to the left, all other terms to the right

-2x^2-40x-((3(2x-1)-(2x-1)-(2x-1)))*2x=-1

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