4(x+2)+7=6(x+1)+2

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Solution for 4(x+2)+7=6(x+1)+2 equation: 



4(x+2)+7=6(x+1)+2

We move all terms to the left:

4(x+2)+7-(6(x+1)+2)=0

We multiply parentheses

4x-(6(x+1)+2)+8+7=0



We calculate terms in parentheses: -(6(x+1)+2), so:

6(x+1)+2

We multiply parentheses

6x+6+2

We add all the numbers together, and all the variables

6x+8

Back to the equation:

-(6x+8)



We add all the numbers together, and all the variables

4x-(6x+8)+15=0

We get rid of parentheses

4x-6x-8+15=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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