(180-(8x-12))+(6x-20)+4x=180

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Solution for (180-(8x-12))+(6x-20)+4x=180 equation: 



(180-(8x-12))+(6x-20)+4x=180

We move all terms to the left:

(180-(8x-12))+(6x-20)+4x-(180)=0

We add all the numbers together, and all the variables

4x+(180-(8x-12))+(6x-20)-180=0

We get rid of parentheses

4x+(180-(8x-12))+6x-20-180=0



We calculate terms in parentheses: +(180-(8x-12)), so:

180-(8x-12)

determiningTheFunctionDomain
-(8x-12)+180

We get rid of parentheses

-8x+12+180

We add all the numbers together, and all the variables

-8x+192

Back to the equation:

+(-8x+192)



We add all the numbers together, and all the variables

10x+(-8x+192)-200=0

We get rid of parentheses

10x-8x+192-200=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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