(2x+26)+(4x+40)=(3x+51)

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Solution for (2x+26)+(4x+40)=(3x+51) equation: 



(2x+26)+(4x+40)=(3x+51)

We move all terms to the left:

(2x+26)+(4x+40)-((3x+51))=0

We get rid of parentheses

2x+4x-((3x+51))+26+40=0



We calculate terms in parentheses: -((3x+51)), so:

(3x+51)

We get rid of parentheses

3x+51

Back to the equation:

-(3x+51)



We add all the numbers together, and all the variables

6x-(3x+51)+66=0

We get rid of parentheses

6x-3x-51+66=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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