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4(x+2)+40=(x-2)-2x
We move all terms to the left:
4(x+2)+40-((x-2)-2x)=0
We multiply parentheses
4x-((x-2)-2x)+8+40=0
We calculate terms in parentheses: -((x-2)-2x), so:We add all the numbers together, and all the variables
(x-2)-2x
We add all the numbers together, and all the variables
-2x+(x-2)
We get rid of parentheses
-2x+x-2
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
-(-1x-2)
4x-(-1x-2)+48=0
We get rid of parentheses
4x+1x+2+48=0
We add all the numbers together, and all the variables
5x+50=0
We move all terms containing x to the left, all other terms to the right
5x=-50
x=-50/5
x=-10
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