4(x+1)=6(x-1)+5

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Solution for 4(x+1)=6(x-1)+5 equation: 



4(x+1)=6(x-1)+5

We move all terms to the left:

4(x+1)-(6(x-1)+5)=0

We multiply parentheses

4x-(6(x-1)+5)+4=0



We calculate terms in parentheses: -(6(x-1)+5), so:

6(x-1)+5

We multiply parentheses

6x-6+5

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

4x-6x+1+4=0

We add all the numbers together, and all the variables

-2x+5=0

We move all terms containing x to the left, all other terms to the right

-2x=-5

x=-5/-2

x=2+1/2

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