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4(x+1)=3(3+x)
We move all terms to the left:
4(x+1)-(3(3+x))=0
We add all the numbers together, and all the variables
4(x+1)-(3(x+3))=0
We multiply parentheses
4x-(3(x+3))+4=0
We calculate terms in parentheses: -(3(x+3)), so:We get rid of parentheses
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
4x-3x-9+4=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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