4(3+m)=6(m-2)

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Solution for 4(3+m)=6(m-2) equation:



4(3+m)=6(m-2)
We move all terms to the left:
4(3+m)-(6(m-2))=0
We add all the numbers together, and all the variables
4(m+3)-(6(m-2))=0
We multiply parentheses
4m-(6(m-2))+12=0
We calculate terms in parentheses: -(6(m-2)), so:
6(m-2)
We multiply parentheses
6m-12
Back to the equation:
-(6m-12)
We get rid of parentheses
4m-6m+12+12=0
We add all the numbers together, and all the variables
-2m+24=0
We move all terms containing m to the left, all other terms to the right
-2m=-24
m=-24/-2
m=+12

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