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4(x+1)=-3(x-2)+5
We move all terms to the left:
4(x+1)-(-3(x-2)+5)=0
We multiply parentheses
4x-(-3(x-2)+5)+4=0
We calculate terms in parentheses: -(-3(x-2)+5), so:We get rid of parentheses
-3(x-2)+5
We multiply parentheses
-3x+6+5
We add all the numbers together, and all the variables
-3x+11
Back to the equation:
-(-3x+11)
4x+3x-11+4=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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