6(3-2b)=-6(3b-5)

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Solution for 6(3-2b)=-6(3b-5) equation: 



6(3-2b)=-6(3b-5)

We move all terms to the left:

6(3-2b)-(-6(3b-5))=0

We add all the numbers together, and all the variables

6(-2b+3)-(-6(3b-5))=0

We multiply parentheses

-12b-(-6(3b-5))+18=0



We calculate terms in parentheses: -(-6(3b-5)), so:

-6(3b-5)

We multiply parentheses

-18b+30

Back to the equation:

-(-18b+30)



We get rid of parentheses

-12b+18b-30+18=0

We add all the numbers together, and all the variables

6b-12=0

We move all terms containing b to the left, all other terms to the right

6b=12

b=12/6

b=2

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