4(x+1)-x=8(x-1)+6

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Solution for 4(x+1)-x=8(x-1)+6 equation: 



4(x+1)-x=8(x-1)+6

We move all terms to the left:

4(x+1)-x-(8(x-1)+6)=0

We add all the numbers together, and all the variables

-1x+4(x+1)-(8(x-1)+6)=0

We multiply parentheses

-1x+4x-(8(x-1)+6)+4=0



We calculate terms in parentheses: -(8(x-1)+6), so:

8(x-1)+6

We multiply parentheses

8x-8+6

We add all the numbers together, and all the variables

8x-2

Back to the equation:

-(8x-2)



We add all the numbers together, and all the variables

3x-(8x-2)+4=0

We get rid of parentheses

3x-8x+2+4=0

We add all the numbers together, and all the variables

-5x+6=0

We move all terms containing x to the left, all other terms to the right

-5x=-6

x=-6/-5

x=1+1/5

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