2=4y+3(y-4)

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Solution for 2=4y+3(y-4) equation: 



2=4y+3(y-4)

We move all terms to the left:

2-(4y+3(y-4))=0



We calculate terms in parentheses: -(4y+3(y-4)), so:

4y+3(y-4)

We multiply parentheses

4y+3y-12

We add all the numbers together, and all the variables

7y-12

Back to the equation:

-(7y-12)



We get rid of parentheses

-7y+12+2=0

We add all the numbers together, and all the variables

-7y+14=0

We move all terms containing y to the left, all other terms to the right

-7y=-14

y=-14/-7

y=+2

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