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4(x+1)(6x-5)=28
We move all terms to the left:
4(x+1)(6x-5)-(28)=0
We multiply parentheses ..
4(+6x^2-5x+6x-5)-28=0
We multiply parentheses
24x^2-20x+24x-20-28=0
We add all the numbers together, and all the variables
24x^2+4x-48=0
a = 24; b = 4; c = -48;
Δ = b2-4ac
Δ = 42-4·24·(-48)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-68}{2*24}=\frac{-72}{48} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+68}{2*24}=\frac{64}{48} =1+1/3 $
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