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2(v-8)+5=3+3(v-2)
We move all terms to the left:
2(v-8)+5-(3+3(v-2))=0
We multiply parentheses
2v-(3+3(v-2))-16+5=0
We calculate terms in parentheses: -(3+3(v-2)), so:We add all the numbers together, and all the variables
3+3(v-2)
determiningTheFunctionDomain 3(v-2)+3
We multiply parentheses
3v-6+3
We add all the numbers together, and all the variables
3v-3
Back to the equation:
-(3v-3)
2v-(3v-3)-11=0
We get rid of parentheses
2v-3v+3-11=0
We add all the numbers together, and all the variables
-1v-8=0
We move all terms containing v to the left, all other terms to the right
-v=8
v=8/-1
v=-8
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