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4(x+-2)-9=3-(x+5)
We move all terms to the left:
4(x+-2)-9-(3-(x+5))=0
We add all the numbers together, and all the variables
4(x-2)-(3-(x+5))-9=0
We multiply parentheses
4x-(3-(x+5))-8-9=0
We calculate terms in parentheses: -(3-(x+5)), so:We add all the numbers together, and all the variables
3-(x+5)
determiningTheFunctionDomain -(x+5)+3
We get rid of parentheses
-x-5+3
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
-(-1x-2)
4x-(-1x-2)-17=0
We get rid of parentheses
4x+1x+2-17=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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