(3)/(x+1)+(2)/(2x-3)=1

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Solution for (3)/(x+1)+(2)/(2x-3)=1 equation: 



(3)/(x+1)+(2)/(2x-3)=1

We move all terms to the left:

(3)/(x+1)+(2)/(2x-3)-(1)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (2x-3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=3

x!=3/2

x!=1+1/2

x∈R



We calculate fractions


(6x-9)/((x+1)*(2x-3))+(2x+2)/((x+1)*(2x-3))-1=0



We calculate terms in parentheses: +(6x-9)/((x+1)*(2x-3)), so:

6x-9)/((x+1)*(2x-3)

We multiply all the terms by the denominator


6x*((x+1)*(2x-3)-9)

Back to the equation:

+(6x*((x+1)*(2x-3)-9))





We calculate terms in parentheses: +(2x+2)/((x+1)*(2x-3)), so:

2x+2)/((x+1)*(2x-3)

We multiply all the terms by the denominator


2x*((x+1)*(2x-3)+2)

Back to the equation:

+(2x*((x+1)*(2x-3)+2))





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+1)*(2x-3)-9)), so:

6x*((x+1)*(2x-3)-9)





We calculate terms in parentheses: +(2x*((x+1)*(2x-3)+2)), so:

2x*((x+1)*(2x-3)+2)





We calculate terms in parentheses: +(6x*((x+

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