4(w+2)-w=2(w-1)+19

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Solution for 4(w+2)-w=2(w-1)+19 equation: 



4(w+2)-w=2(w-1)+19

We move all terms to the left:

4(w+2)-w-(2(w-1)+19)=0

We add all the numbers together, and all the variables

-1w+4(w+2)-(2(w-1)+19)=0

We multiply parentheses

-1w+4w-(2(w-1)+19)+8=0



We calculate terms in parentheses: -(2(w-1)+19), so:

2(w-1)+19

We multiply parentheses

2w-2+19

We add all the numbers together, and all the variables

2w+17

Back to the equation:

-(2w+17)



We add all the numbers together, and all the variables

3w-(2w+17)+8=0

We get rid of parentheses

3w-2w-17+8=0

We add all the numbers together, and all the variables

w-9=0

We move all terms containing w to the left, all other terms to the right

w=9

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