-5u2+7u+4=0

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Solution for -5u2+7u+4=0 equation:



-5u^2+7u+4=0
a = -5; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·(-5)·4
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{129}}{2*-5}=\frac{-7-\sqrt{129}}{-10} $
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{129}}{2*-5}=\frac{-7+\sqrt{129}}{-10} $

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