4(v+6)=-2(8v-5)+8v

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Solution for 4(v+6)=-2(8v-5)+8v equation: 



4(v+6)=-2(8v-5)+8v

We move all terms to the left:

4(v+6)-(-2(8v-5)+8v)=0

We multiply parentheses

4v-(-2(8v-5)+8v)+24=0



We calculate terms in parentheses: -(-2(8v-5)+8v), so:

-2(8v-5)+8v

We add all the numbers together, and all the variables

8v-2(8v-5)

We multiply parentheses

8v-16v+10

We add all the numbers together, and all the variables

-8v+10

Back to the equation:

-(-8v+10)



We get rid of parentheses

4v+8v-10+24=0

We add all the numbers together, and all the variables

12v+14=0

We move all terms containing v to the left, all other terms to the right

12v=-14

v=-14/12

v=-1+1/6

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