3x(6-x)=9

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Solution for 3x(6-x)=9 equation:



3x(6-x)=9
We move all terms to the left:
3x(6-x)-(9)=0
We add all the numbers together, and all the variables
3x(-1x+6)-9=0
We multiply parentheses
-3x^2+18x-9=0
a = -3; b = 18; c = -9;
Δ = b2-4ac
Δ = 182-4·(-3)·(-9)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{6}}{2*-3}=\frac{-18-6\sqrt{6}}{-6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{6}}{2*-3}=\frac{-18+6\sqrt{6}}{-6} $

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