4(v+4)=-2v+22

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Solution for 4(v+4)=-2v+22 equation: 



4(v+4)=-2v+22

We move all terms to the left:

4(v+4)-(-2v+22)=0

We multiply parentheses

4v-(-2v+22)+16=0

We get rid of parentheses

4v+2v-22+16=0

We add all the numbers together, and all the variables

6v-6=0

We move all terms containing v to the left, all other terms to the right

6v=6

v=6/6

v=1

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