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-3/n+5/2n=-6
We move all terms to the left:
-3/n+5/2n-(-6)=0
Domain of the equation: n!=0
n∈R
Domain of the equation: 2n!=0We add all the numbers together, and all the variables
n!=0/2
n!=0
n∈R
-3/n+5/2n+6=0
We calculate fractions
(-6n)/2n^2+5n/2n^2+6=0
We multiply all the terms by the denominator
(-6n)+5n+6*2n^2=0
We add all the numbers together, and all the variables
5n+(-6n)+6*2n^2=0
Wy multiply elements
12n^2+5n+(-6n)=0
We get rid of parentheses
12n^2+5n-6n=0
We add all the numbers together, and all the variables
12n^2-1n=0
a = 12; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*12}=\frac{0}{24} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*12}=\frac{2}{24} =1/12 $
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