4(u-5)-7=-4(-4u+3)-2u

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Solution for 4(u-5)-7=-4(-4u+3)-2u equation: 



4(u-5)-7=-4(-4u+3)-2u

We move all terms to the left:

4(u-5)-7-(-4(-4u+3)-2u)=0

We multiply parentheses

4u-(-4(-4u+3)-2u)-20-7=0



We calculate terms in parentheses: -(-4(-4u+3)-2u), so:

-4(-4u+3)-2u

We add all the numbers together, and all the variables

-2u-4(-4u+3)

We multiply parentheses

-2u+16u-12

We add all the numbers together, and all the variables

14u-12

Back to the equation:

-(14u-12)



We add all the numbers together, and all the variables

4u-(14u-12)-27=0

We get rid of parentheses

4u-14u+12-27=0

We add all the numbers together, and all the variables

-10u-15=0

We move all terms containing u to the left, all other terms to the right

-10u=15

u=15/-10

u=-1+1/2

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