-b+5(4b-4)=10b-10-2b

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Solution for -b+5(4b-4)=10b-10-2b equation: 



-b+5(4b-4)=10b-10-2b

We move all terms to the left:

-b+5(4b-4)-(10b-10-2b)=0

We add all the numbers together, and all the variables

-b+5(4b-4)-(8b-10)=0

We add all the numbers together, and all the variables

-1b+5(4b-4)-(8b-10)=0

We multiply parentheses

-1b+20b-(8b-10)-20=0

We get rid of parentheses

-1b+20b-8b+10-20=0

We add all the numbers together, and all the variables

11b-10=0

We move all terms containing b to the left, all other terms to the right

11b=10

b=10/11

b=10/11

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