4(u-3)-5=-2(-9u+1)-5u

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Solution for 4(u-3)-5=-2(-9u+1)-5u equation: 



4(u-3)-5=-2(-9u+1)-5u

We move all terms to the left:

4(u-3)-5-(-2(-9u+1)-5u)=0

We multiply parentheses

4u-(-2(-9u+1)-5u)-12-5=0



We calculate terms in parentheses: -(-2(-9u+1)-5u), so:

-2(-9u+1)-5u

We add all the numbers together, and all the variables

-5u-2(-9u+1)

We multiply parentheses

-5u+18u-2

We add all the numbers together, and all the variables

13u-2

Back to the equation:

-(13u-2)



We add all the numbers together, and all the variables

4u-(13u-2)-17=0

We get rid of parentheses

4u-13u+2-17=0

We add all the numbers together, and all the variables

-9u-15=0

We move all terms containing u to the left, all other terms to the right

-9u=15

u=15/-9

u=-1+2/3

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