4c+14=3c+35

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Solution for 4c+14=3c+35 equation: 



4c+14=3c+35

We move all terms to the left:

4c+14-(3c+35)=0

We get rid of parentheses

4c-3c-35+14=0

We add all the numbers together, and all the variables

c-21=0

We move all terms containing c to the left, all other terms to the right

c=21

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