4(u-2)=2u+7-3(-4u-1)

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Solution for 4(u-2)=2u+7-3(-4u-1) equation: 



4(u-2)=2u+7-3(-4u-1)

We move all terms to the left:

4(u-2)-(2u+7-3(-4u-1))=0

We multiply parentheses

4u-(2u+7-3(-4u-1))-8=0



We calculate terms in parentheses: -(2u+7-3(-4u-1)), so:

2u+7-3(-4u-1)

determiningTheFunctionDomain
2u-3(-4u-1)+7

We multiply parentheses

2u+12u+3+7

We add all the numbers together, and all the variables

14u+10

Back to the equation:

-(14u+10)



We get rid of parentheses

4u-14u-10-8=0

We add all the numbers together, and all the variables

-10u-18=0

We move all terms containing u to the left, all other terms to the right

-10u=18

u=18/-10

u=-1+4/5

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