4(u+3)-3u=2(u+3)

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Solution for 4(u+3)-3u=2(u+3) equation: 



4(u+3)-3u=2(u+3)

We move all terms to the left:

4(u+3)-3u-(2(u+3))=0

We add all the numbers together, and all the variables

-3u+4(u+3)-(2(u+3))=0

We multiply parentheses

-3u+4u-(2(u+3))+12=0



We calculate terms in parentheses: -(2(u+3)), so:

2(u+3)

We multiply parentheses

2u+6

Back to the equation:

-(2u+6)



We add all the numbers together, and all the variables

u-(2u+6)+12=0

We get rid of parentheses

u-2u-6+12=0

We add all the numbers together, and all the variables

-1u+6=0

We move all terms containing u to the left, all other terms to the right

-u=-6

u=-6/-1

u=+6

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