4(u+1)=32

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Solution for 4(u+1)=32 equation: 



4(u+1)=32

We move all terms to the left:

4(u+1)-(32)=0

We multiply parentheses

4u+4-32=0

We add all the numbers together, and all the variables

4u-28=0

We move all terms containing u to the left, all other terms to the right

4u=28

u=28/4

u=7

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