2(4-2c)=7(c+1)

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Solution for 2(4-2c)=7(c+1) equation: 



2(4-2c)=7(c+1)

We move all terms to the left:

2(4-2c)-(7(c+1))=0

We add all the numbers together, and all the variables

2(-2c+4)-(7(c+1))=0

We multiply parentheses

-4c-(7(c+1))+8=0



We calculate terms in parentheses: -(7(c+1)), so:

7(c+1)

We multiply parentheses

7c+7

Back to the equation:

-(7c+7)



We get rid of parentheses

-4c-7c-7+8=0

We add all the numbers together, and all the variables

-11c+1=0

We move all terms containing c to the left, all other terms to the right

-11c=-1

c=-1/-11

c=1/11

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