3(g-3)=6(g+2)

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Solution for 3(g-3)=6(g+2) equation: 



3(g-3)=6(g+2)

We move all terms to the left:

3(g-3)-(6(g+2))=0

We multiply parentheses

3g-(6(g+2))-9=0



We calculate terms in parentheses: -(6(g+2)), so:

6(g+2)

We multiply parentheses

6g+12

Back to the equation:

-(6g+12)



We get rid of parentheses

3g-6g-12-9=0

We add all the numbers together, and all the variables

-3g-21=0

We move all terms containing g to the left, all other terms to the right

-3g=21

g=21/-3

g=-7

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