4(u+1)+5=6(u-1)=u

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Solution for 4(u+1)+5=6(u-1)=u equation:



4(u+1)+5=6(u-1)=u
We move all terms to the left:
4(u+1)+5-(6(u-1))=0
We multiply parentheses
4u-(6(u-1))+4+5=0
We calculate terms in parentheses: -(6(u-1)), so:
6(u-1)
We multiply parentheses
6u-6
Back to the equation:
-(6u-6)
We add all the numbers together, and all the variables
4u-(6u-6)+9=0
We get rid of parentheses
4u-6u+6+9=0
We add all the numbers together, and all the variables
-2u+15=0
We move all terms containing u to the left, all other terms to the right
-2u=-15
u=-15/-2
u=7+1/2

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